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0.4x^2=6
We move all terms to the left:
0.4x^2-(6)=0
a = 0.4; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·0.4·(-6)
Δ = 9.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{9.6}}{2*0.4}=\frac{0-\sqrt{9.6}}{0.8} =-\frac{\sqrt{}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{9.6}}{2*0.4}=\frac{0+\sqrt{9.6}}{0.8} =\frac{\sqrt{}}{0.8} $
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